When the sum of the measures of two angles is 90°, the angles are called complementary angles. Each of them is called the complement of the other. Two angles are called adjacent angles if they have a common vertex
and a common arm but no common interior points. When the sum of the measures of two angles is 180°, the angles are called supplementary angles. Each of them is called a supplement of the other.
Angles Practice Test
When two lines are intersected by a transversal, eight angles are formed. These angles can be classified as 4 interior angles, 4 exterior angles, 4 pairs of corresponding angles, 2 pairs of alternate interior angles, 2 pairs of alternate exterior angles, and two pairs of interior angles on the same side of the transversal.
Test Name 
Angles Test Prep 
Type of Question 
Multiple Choice Question Answers 
Subject 
Math 
Total Question 
10 
Test Type 
Sample / Mock Test 
Editable & Printable PDF / Doc 
YES (Download link is given below) 
Available of Answers 
YES 
Difficulty Level 
Elementary Geometry 
Angles Practice Test Question Answers
Elementary Geometry: SET 1
1. In the following a pair of corresponding angles is

🔘 A. ∠1, ∠2 
🔘 B. ∠2, ∠2 
🔘 C. ∠3, ∠6 
🔘 D. ∠4, ∠5 
🔘 E. ∠3, ∠7 
Show Answers
Answer:∠3, ∠7
2. In the following figure ABEF, EDCB and ∠APE is 39°. Find ∠CQF.

🔘 A. ∠CQF= 28^{0} 
🔘 B. ∠CQF= 39^{0} 
🔘 C. ∠CQF= 93^{0} 
🔘 D. ∠CQF= 139^{0} 
🔘 E. ∠CQF= 141^{0} 
Show Answers
Answer:∠CQF= 141^{0} (Since EDBC and AB is a transversal, so so ∠QBP = ∠APE
[Corresponding angles] or ∠QBP = 39° Now, ABEF and BC is a transversal. Therefore, ∠FQB = ∠QBP [Alternate interior angles] Also, ∠CQF + ∠FQB = 180° [Linear pair] ∠CQF = 180° – 39°
3. Out of a pair of complementary angles, one is twothird of the other. Find the angles. 
🔘 A. 18° 
🔘 B. 36° 
🔘 C. 54° 
🔘 D. 90° 
🔘 E. 180° 
Show Answers
Answer:B. 36° Let one angle be x. So, other angle = 90° – x Thus,
(2/3)× x = 90° – x or 5x = 270° or x=54° So, one angle = 54° and the other angle = 90° – 54°= 36°.
4. In the following figure CD intersects the line AB at F, ∠ CFB = 50° and ∠ EFA = ∠ AFD. Find the measure of ∠ EFC.

🔘 A. 50° 
🔘 B. 80° 
🔘 C. 90° 
🔘 D. 120° 
🔘 E. 180° 
Show Answers
Answer:B 80° Solution (∠CFB = ∠AFD (Vertically opposite angles) So, x = 50° But ∠EFA = ∠AFD which gives ∠EFA = 50° Now ∠CFB + ∠EFA + ∠EFC = 180° or, 50° + 50° + ∠EFC = 180° Thus, ∠EFC = 80°. [As AB is a straight line].
5. If the complement of an angle is 79°, then the angle will be of 
🔘 A. 1° 
🔘 B. 10° 
🔘 C. 11° 
🔘 D. 111° 
🔘 E. 110° 
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Answer: C C. 11°
6. In the following figure find the value of x is

🔘 A. 46° 
🔘 B. 90° 
🔘 C. 100° 
🔘 D. 110° 
🔘 E. 150° 
Show Answers
Answer:E. 150° (Sum of all angle about a point given in the figure are equal to 360° Then, 100o + 46o + 64o + x = 360°)
7. In the following figure if AB  CD, ∠ APQ = 50° and ∠PRD = 130°, then ∠ QPR is

🔘 A. 20° 
🔘 B. 50° 
🔘 C. 80° 
🔘 D. 90° 
🔘 E. 130° 
Show Answers
Answer: C. 80° (Hints: ∠APQ + ∠QPR = 130° )
8. If angle A and angle B are supplementary and the measure of angle A is 60°, then the measure of angle B is 
🔘 A. 30° 
🔘 B. 60° 
🔘 C. 80° 
🔘 D. 90° 
🔘 E. 120° 
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Answer:E. 120° (Hinsta P + Q = 180°)
9. The measure of an angle which is four times its supplement is 
🔘 A. 36° 
🔘 B. 90° 
🔘 C. 110° 
🔘 D. 120° 
🔘 E. 144° 
Show Answers
Answer:E. 144° ( supplement angle = (180° – x) or x = 4 (180° – x)
10. In the following figure find the value of y

🔘 A. 10° 
🔘 B. 20° 
🔘 C. 33° 
🔘 D. 45° 
🔘 E. 60° 
Show Answers
Answer:B. 20° (sol: Sum of all angle about a straight line given in the figure are equal to 180°
Then, 6y + y + 2y = 180° or 9y = 180°) or y=20°
Angles Practice Test Question Answers [PDF Worksheet]
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